Updating two tables in oracle Mobile sex chat in the philippines

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you may have to add an update trigger to the view itself. comment with the statement you are trying to run..feedback off;create table sales_order( order_id numeric(10,0),total numeric(8,2) );create table order_item(order_id numeric(10,0),quantity numeric(10,0),price numeric(8,2));insert into sales_order (order_id) values (1);insert into sales_order (order_id) values (2);insert into sales_order (order_id) values (3);insert into order_item (order_id, quantity, price) values (1,1,15.0);insert into order_item (order_id, quantity, price) values (1,2,10.0);insert into order_item (order_id, quantity, price) values (1,3, 5.0);insert into order_item (order_id, quantity, price) values (2,1,15.0);insert into order_item (order_id, quantity, price) values (2,2,15.0);insert into order_item (order_id, quantity, price) values (2,2, 5.0);insert into order_item (order_id, quantity, price) values (2,5,10.0);insert into order_item (order_id, quantity, price) values (3,3,15.0);update sales_orderset total = (select sum(quantity*price) from order_item where order_id = sales_order.order_id);select * from sales_order;drop table sales_order;drop table order_item; ORDER_ID TOTAL ---------------------- ---------------------- 1 50 2 105 3 45 update (select feed_year from FEEDBACK f inner join APPOINTMENTS ap on f.

I have added a new column to an existing sales_order table to store the total value of the order.

START_DATE, SYSDATE) Our query is a thing of beauty, but you must have noticed that it does not return a complete list of our friends.The syntax for a multi-table select statement is as follows: Run that and see what you get. However, when I run the query, I get 2 rows for Rachel – one for her current phone number and another for her previous one. Of course we can simply add to our column list and look to see which record is current. END_DATE IS NULL” to our Where clause and exclude end-dated rows in that way. Expand the query to display our friends’ addresses: to do this you’ll need to join the FRIEND_ADDRESS and ADDRESS tables. You’ve probably already guessed that I’m setting you up, but it’s important that we make these mistakes now, so we can learn about them. But what if Rachel had told us that she was changing her phone number next month and we’d put in a future end-date? SQL select * from new_emp; ID FNAME LNAME START_DAT END_DATE SALARY CITY ---- ---------- ---------- --------- --------- ---------- ---------- DESCRIPTION --------------- 01 Jason Martin 25-JUL-96 25-JUL-06 1235.56 Toronto Programmer 02 Alison Mathews 21-MAR-76 21-FEB-86 6662.78 Vancouver Tester 03 James Smith 12-DEC-78 15-MAR-90 6545.78 Vancouver Tester ID FNAME LNAME START_DAT END_DATE SALARY CITY ---- ---------- ---------- --------- --------- ---------- ---------- DESCRIPTION --------------- 04 Celia Rice 24-OCT-82 21-APR-99 2345.78 Vancouver Manager 05 Robert Black 15-JAN-84 08-AUG-98 2335.78 Vancouver Tester 06 Linda Green 30-JUL-87 04-JAN-96 4323.78 New York Tester ID FNAME LNAME START_DAT END_DATE SALARY CITY ---- ---------- ---------- --------- --------- ---------- ---------- DESCRIPTION --------------- 07 David Larry 31-DEC-90 12-FEB-98 7898.78 New York Manager 08 James Cat 17-SEP-96 15-APR-02 1233.78 Vancouver Tester 8 rows selected.it solved my problem to some i want to know can we update multiple values at the same time using a single querry. Take a look at this example:update ( select profit_bonus, merit_bonus from employee_bonus b inner join employees e on b.employee_id = e.employee_id where e.bonus_eligible = 'N' ) t set t.profit_bonus = 0, t.merit_bonus = 0; Hi David, This time where the employee is eligible for a bonus :-)update ( select b.bonus, e.salary from employee_bonus b inner join employees e on b.employee_id = e.employee_id where e.bonus_eligible = 'Y' ) t set t.bonus = 0.1 * t.salary Hope this helps!

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